13414111324331 has 2 divisors, whose sum is σ = 13414111324332. Its totient is φ = 13414111324330.

The previous prime is 13414111324321. The next prime is 13414111324333. The reversal of 13414111324331 is 13342311141431.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13414111324331 - 2⁶ = 13414111324267 is a prime.

It is a super-2 number, since 2×13414111324331² (a number of 27 digits) contains 22 as substring.

Together with 13414111324333, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13414111324333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6707055662165 + 6707055662166.

It is an arithmetic number, because the mean of its divisors is an integer number (6707055662166).

Almost surely, 2^{13414111324331} is an apocalyptic number.

13414111324331 is a deficient number, since it is larger than the sum of its proper divisors (1).

13414111324331 is an equidigital number, since it uses as much as digits as its factorization.

13414111324331 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10368, while the sum is 32.

Adding to 13414111324331 its reverse (13342311141431), we get a palindrome (26756422465762).

The spelling of 13414111324331 in words is "thirteen trillion, four hundred fourteen billion, one hundred eleven million, three hundred twenty-four thousand, three hundred thirty-one".