Base | Representation |
---|---|
bin | 111110011111100010… |
… | …1100101000101011111 |
3 | 110211101210111222001211 |
4 | 1330333011211011133 |
5 | 4144321304212112 |
6 | 141352435245251 |
7 | 12460442456326 |
oct | 1747705450537 |
9 | 424353458054 |
10 | 134202413407 |
11 | 51a07844567 |
12 | 22014149827 |
13 | c869716b9a |
14 | 66d166d0bd |
15 | 3756c6d0a7 |
hex | 1f3f16515f |
134202413407 has 2 divisors, whose sum is σ = 134202413408. Its totient is φ = 134202413406.
The previous prime is 134202413381. The next prime is 134202413431. The reversal of 134202413407 is 704314202431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134202413407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134202413497) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67101206703 + 67101206704.
It is an arithmetic number, because the mean of its divisors is an integer number (67101206704).
Almost surely, 2134202413407 is an apocalyptic number.
134202413407 is a deficient number, since it is larger than the sum of its proper divisors (1).
134202413407 is an equidigital number, since it uses as much as digits as its factorization.
134202413407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 31.
Adding to 134202413407 its reverse (704314202431), we get a palindrome (838516615838).
The spelling of 134202413407 in words is "one hundred thirty-four billion, two hundred two million, four hundred thirteen thousand, four hundred seven".
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