Base | Representation |
---|---|
bin | 111110011111100010… |
… | …1100101000101000101 |
3 | 110211101210111222000212 |
4 | 1330333011211011011 |
5 | 4144321304212011 |
6 | 141352435245205 |
7 | 12460442456261 |
oct | 1747705450505 |
9 | 424353458025 |
10 | 134202413381 |
11 | 51a07844543 |
12 | 22014149805 |
13 | c869716b7a |
14 | 66d166d0a1 |
15 | 3756c6d08b |
hex | 1f3f165145 |
134202413381 has 2 divisors, whose sum is σ = 134202413382. Its totient is φ = 134202413380.
The previous prime is 134202413357. The next prime is 134202413407. The reversal of 134202413381 is 183314202431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 122109012481 + 12093400900 = 349441^2 + 109970^2 .
It is a cyclic number.
It is not a de Polignac number, because 134202413381 - 214 = 134202396997 is a prime.
It is a super-2 number, since 2×1342024133812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134202413881) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67101206690 + 67101206691.
It is an arithmetic number, because the mean of its divisors is an integer number (67101206691).
Almost surely, 2134202413381 is an apocalyptic number.
It is an amenable number.
134202413381 is a deficient number, since it is larger than the sum of its proper divisors (1).
134202413381 is an equidigital number, since it uses as much as digits as its factorization.
134202413381 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 32.
The spelling of 134202413381 in words is "one hundred thirty-four billion, two hundred two million, four hundred thirteen thousand, three hundred eighty-one".
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