Base | Representation |
---|---|
bin | 111110011111100110… |
… | …1010100001000001101 |
3 | 110211101221022222112121 |
4 | 1330333031110020031 |
5 | 4144322314103401 |
6 | 141352550532541 |
7 | 12460465633063 |
oct | 1747715241015 |
9 | 424357288477 |
10 | 134204441101 |
11 | 51a089a9a45 |
12 | 22014967151 |
13 | c869c76ac3 |
14 | 66d1a3a033 |
15 | 375701dca1 |
hex | 1f3f35420d |
134204441101 has 2 divisors, whose sum is σ = 134204441102. Its totient is φ = 134204441100.
The previous prime is 134204441093. The next prime is 134204441153. The reversal of 134204441101 is 101144402431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 121406949225 + 12797491876 = 348435^2 + 113126^2 .
It is a cyclic number.
It is not a de Polignac number, because 134204441101 - 23 = 134204441093 is a prime.
It is a super-2 number, since 2×1342044411012 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134204441191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67102220550 + 67102220551.
It is an arithmetic number, because the mean of its divisors is an integer number (67102220551).
Almost surely, 2134204441101 is an apocalyptic number.
It is an amenable number.
134204441101 is a deficient number, since it is larger than the sum of its proper divisors (1).
134204441101 is an equidigital number, since it uses as much as digits as its factorization.
134204441101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 134204441101 its reverse (101144402431), we get a palindrome (235348843532).
The spelling of 134204441101 in words is "one hundred thirty-four billion, two hundred four million, four hundred forty-one thousand, one hundred one".
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