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134209436981 is a prime number
BaseRepresentation
bin111110011111110000…
…0010111110100110101
3110211102021201210121012
41330333200113310311
54144330103440411
6141353250002005
712460556251244
oct1747740276465
9424367653535
10134209436981
1151a10801474
1222016576305
13c86b005a49
1466d257a95b
1537576a918b
hex1f3f817d35

134209436981 has 2 divisors, whose sum is σ = 134209436982. Its totient is φ = 134209436980.

The previous prime is 134209436957. The next prime is 134209436983. The reversal of 134209436981 is 189634902431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98554556356 + 35654880625 = 313934^2 + 188825^2 .

It is a cyclic number.

It is not a de Polignac number, because 134209436981 - 26 = 134209436917 is a prime.

It is a super-2 number, since 2×1342094369812 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 134209436983, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134209436983) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67104718490 + 67104718491.

It is an arithmetic number, because the mean of its divisors is an integer number (67104718491).

Almost surely, 2134209436981 is an apocalyptic number.

It is an amenable number.

134209436981 is a deficient number, since it is larger than the sum of its proper divisors (1).

134209436981 is an equidigital number, since it uses as much as digits as its factorization.

134209436981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1119744, while the sum is 50.

The spelling of 134209436981 in words is "one hundred thirty-four billion, two hundred nine million, four hundred thirty-six thousand, nine hundred eighty-one".