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1342101441157 is a prime number
BaseRepresentation
bin10011100001111011011…
…110101100101010000101
311202022012100122021001121
4103201323132230222011
5133442110432104112
62504315231353541
7165651345010651
oct23417336545205
94668170567047
101342101441157
11478200303064
121981370828b1
13997376507b9
1448d5ac99a61
1524da015b407
hex1387b7aca85

1342101441157 has 2 divisors, whose sum is σ = 1342101441158. Its totient is φ = 1342101441156.

The previous prime is 1342101441119. The next prime is 1342101441167. The reversal of 1342101441157 is 7511441012431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1065878667396 + 276222773761 = 1032414^2 + 525569^2 .

It is an emirp because it is prime and its reverse (7511441012431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1342101441157 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1342101441167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671050720578 + 671050720579.

It is an arithmetic number, because the mean of its divisors is an integer number (671050720579).

Almost surely, 21342101441157 is an apocalyptic number.

It is an amenable number.

1342101441157 is a deficient number, since it is larger than the sum of its proper divisors (1).

1342101441157 is an equidigital number, since it uses as much as digits as its factorization.

1342101441157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13440, while the sum is 34.

Adding to 1342101441157 its reverse (7511441012431), we get a palindrome (8853542453588).

The spelling of 1342101441157 in words is "one trillion, three hundred forty-two billion, one hundred one million, four hundred forty-one thousand, one hundred fifty-seven".