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134210314213 is a prime number
BaseRepresentation
bin111110011111110001…
…1101101111111100101
3110211102100101100221021
41330333203231333211
54144330320023323
6141353320451141
712460566563623
oct1747743557745
9424370340837
10134210314213
1151a11250558
1222016919ab1
13c86b252111
1466d2728513
1537577ce05d
hex1f3f8edfe5

134210314213 has 2 divisors, whose sum is σ = 134210314214. Its totient is φ = 134210314212.

The previous prime is 134210314123. The next prime is 134210314253. The reversal of 134210314213 is 312413012431.

Together with previous prime (134210314123) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130290677764 + 3919636449 = 360958^2 + 62607^2 .

It is a cyclic number.

It is not a de Polignac number, because 134210314213 - 29 = 134210313701 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134210314253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67105157106 + 67105157107.

It is an arithmetic number, because the mean of its divisors is an integer number (67105157107).

Almost surely, 2134210314213 is an apocalyptic number.

It is an amenable number.

134210314213 is a deficient number, since it is larger than the sum of its proper divisors (1).

134210314213 is an equidigital number, since it uses as much as digits as its factorization.

134210314213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 134210314213 its reverse (312413012431), we get a palindrome (446623326644).

The spelling of 134210314213 in words is "one hundred thirty-four billion, two hundred ten million, three hundred fourteen thousand, two hundred thirteen".