Base | Representation |
---|---|
bin | 111110011111110111… |
… | …0001011001011001101 |
3 | 110211102112112121211121 |
4 | 1330333232023023031 |
5 | 4144332020231211 |
6 | 141353455320541 |
7 | 12460632101032 |
oct | 1747756131315 |
9 | 424375477747 |
10 | 134213055181 |
11 | 51a12852917 |
12 | 22017820151 |
13 | c86b9a18aa |
14 | 66d2c3d389 |
15 | 3757b71271 |
hex | 1f3fb8b2cd |
134213055181 has 2 divisors, whose sum is σ = 134213055182. Its totient is φ = 134213055180.
The previous prime is 134213055161. The next prime is 134213055283. The reversal of 134213055181 is 181550312431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 111910320900 + 22302734281 = 334530^2 + 149341^2 .
It is a cyclic number.
It is not a de Polignac number, because 134213055181 - 223 = 134204666573 is a prime.
It is a super-2 number, since 2×1342130551812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134213055161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67106527590 + 67106527591.
It is an arithmetic number, because the mean of its divisors is an integer number (67106527591).
Almost surely, 2134213055181 is an apocalyptic number.
It is an amenable number.
134213055181 is a deficient number, since it is larger than the sum of its proper divisors (1).
134213055181 is an equidigital number, since it uses as much as digits as its factorization.
134213055181 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 34.
The spelling of 134213055181 in words is "one hundred thirty-four billion, two hundred thirteen million, fifty-five thousand, one hundred eighty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •