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1342142111437 is a prime number
BaseRepresentation
bin10011100001111101111…
…001110101111011001101
311202022022012011112012021
4103201331321311323031
5133442201340031222
62504323243210141
7165652350500131
oct23417571657315
94668265145167
101342142111437
11478221261266
12198148816951
1399742bc045a
1448d624453c1
1524da39e1ac7
hex1387de75ecd

1342142111437 has 2 divisors, whose sum is σ = 1342142111438. Its totient is φ = 1342142111436.

The previous prime is 1342142111411. The next prime is 1342142111459. The reversal of 1342142111437 is 7341112412431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1236041427076 + 106100684361 = 1111774^2 + 325731^2 .

It is a cyclic number.

It is not a de Polignac number, because 1342142111437 - 235 = 1307782373069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1342142111407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671071055718 + 671071055719.

It is an arithmetic number, because the mean of its divisors is an integer number (671071055719).

Almost surely, 21342142111437 is an apocalyptic number.

It is an amenable number.

1342142111437 is a deficient number, since it is larger than the sum of its proper divisors (1).

1342142111437 is an equidigital number, since it uses as much as digits as its factorization.

1342142111437 is an evil number, because the sum of its binary digits is even.

The product of its digits is 16128, while the sum is 34.

Adding to 1342142111437 its reverse (7341112412431), we get a palindrome (8683254523868).

The spelling of 1342142111437 in words is "one trillion, three hundred forty-two billion, one hundred forty-two million, one hundred eleven thousand, four hundred thirty-seven".