1342202141440 has 36 divisors (see below), whose sum is σ = 3214993569984. Its totient is φ = 536880856064.

The previous prime is 1342202141419. The next prime is 1342202141459. The reversal of 1342202141440 is 441412022431.

It is a super-2 number, since 2×1342202141440² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1342202141399 and 1342202141408.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 524296432 + ... + 524298991.

It is an arithmetic number, because the mean of its divisors is an integer number (89305376944).

Almost surely, 2^{1342202141440} is an apocalyptic number.

1342202141440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1342202141440 is an abundant number, since it is smaller than the sum of its proper divisors (1872791428544).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1342202141440 is an equidigital number, since it uses as much as digits as its factorization.

1342202141440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1048595444 (or 1048595430 counting only the distinct ones).

The product of its (nonzero) digits is 6144, while the sum is 28.

Adding to 1342202141440 its reverse (441412022431), we get a palindrome (1783614163871).

The spelling of 1342202141440 in words is "one trillion, three hundred forty-two billion, two hundred two million, one hundred forty-one thousand, four hundred forty".