Base | Representation |
---|---|
bin | 10011100010000011010… |
… | …001111110000101100111 |
3 | 11202022112110220201101022 |
4 | 103202003101332011213 |
5 | 133442342433304112 |
6 | 2504340224521355 |
7 | 165654524331644 |
oct | 23420321760547 |
9 | 4668473821338 |
10 | 1342232322407 |
11 | 478268177089 |
12 | 198172a8025b |
13 | 997587b7422 |
14 | 48d70408dcb |
15 | 24dab8b0d72 |
hex | 1388347e167 |
1342232322407 has 2 divisors, whose sum is σ = 1342232322408. Its totient is φ = 1342232322406.
The previous prime is 1342232322373. The next prime is 1342232322451. The reversal of 1342232322407 is 7042232322431.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1342232322407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1342232822407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671116161203 + 671116161204.
It is an arithmetic number, because the mean of its divisors is an integer number (671116161204).
Almost surely, 21342232322407 is an apocalyptic number.
1342232322407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342232322407 is an equidigital number, since it uses as much as digits as its factorization.
1342232322407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96768, while the sum is 35.
Adding to 1342232322407 its reverse (7042232322431), we get a palindrome (8384464644838).
The spelling of 1342232322407 in words is "one trillion, three hundred forty-two billion, two hundred thirty-two million, three hundred twenty-two thousand, four hundred seven".
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