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13423021115249 is a prime number
BaseRepresentation
bin1100001101010100101001…
…1001111100011101110001
31202112020011102100201112102
43003111022121330131301
53224410321401141444
644314241211110145
72553531655634444
oct303251231743561
952466142321472
1013423021115249
114305742533779
12160957a742355
13764a29869835
1434596b81165b
1518426c16184e
hexc354a67c771

13423021115249 has 2 divisors, whose sum is σ = 13423021115250. Its totient is φ = 13423021115248.

The previous prime is 13423021115201. The next prime is 13423021115297. The reversal of 13423021115249 is 94251112032431.

It is a balanced prime because it is at equal distance from previous prime (13423021115201) and next prime (13423021115297).

It can be written as a sum of positive squares in only one way, i.e., 12327507213025 + 1095513902224 = 3511055^2 + 1046668^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13423021115249 is a prime.

It is not a weakly prime, because it can be changed into another prime (13423021115299) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6711510557624 + 6711510557625.

It is an arithmetic number, because the mean of its divisors is an integer number (6711510557625).

Almost surely, 213423021115249 is an apocalyptic number.

It is an amenable number.

13423021115249 is a deficient number, since it is larger than the sum of its proper divisors (1).

13423021115249 is an equidigital number, since it uses as much as digits as its factorization.

13423021115249 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 38.

The spelling of 13423021115249 in words is "thirteen trillion, four hundred twenty-three billion, twenty-one million, one hundred fifteen thousand, two hundred forty-nine".