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13423130551 is a prime number
BaseRepresentation
bin11001000000001010…
…01011011110110111
31021122110222200110101
430200011023132313
5204442310134201
610055544134531
7653431504255
oct144005133667
937573880411
1013423130551
115769009726
122727467447
13135bc515cc
14914a315d5
15538683d01
hex32014b7b7

13423130551 has 2 divisors, whose sum is σ = 13423130552. Its totient is φ = 13423130550.

The previous prime is 13423130503. The next prime is 13423130557. The reversal of 13423130551 is 15503132431.

It is a happy number.

13423130551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (15503132431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13423130551 - 215 = 13423097783 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13423130557) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6711565275 + 6711565276.

It is an arithmetic number, because the mean of its divisors is an integer number (6711565276).

Almost surely, 213423130551 is an apocalyptic number.

13423130551 is a deficient number, since it is larger than the sum of its proper divisors (1).

13423130551 is an equidigital number, since it uses as much as digits as its factorization.

13423130551 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 13423130551 its reverse (15503132431), we get a palindrome (28926262982).

The spelling of 13423130551 in words is "thirteen billion, four hundred twenty-three million, one hundred thirty thousand, five hundred fifty-one".