1342314402311 has 2 divisors, whose sum is σ = 1342314402312. Its totient is φ = 1342314402310.

The previous prime is 1342314402293. The next prime is 1342314402313. The reversal of 1342314402311 is 1132044132431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1342314402311 - 2¹⁰ = 1342314401287 is a prime.

It is a Sophie Germain prime.

Together with 1342314402313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1342314402313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671157201155 + 671157201156.

It is an arithmetic number, because the mean of its divisors is an integer number (671157201156).

Almost surely, 2^{1342314402311} is an apocalyptic number.

1342314402311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1342314402311 is an equidigital number, since it uses as much as digits as its factorization.

1342314402311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1342314402311 its reverse (1132044132431), we get a palindrome (2474358534742).

The spelling of 1342314402311 in words is "one trillion, three hundred forty-two billion, three hundred fourteen million, four hundred two thousand, three hundred eleven".