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13423843709 is a prime number
BaseRepresentation
bin11001000000001111…
…11001100101111101
31021122112022220201122
430200013321211331
5204443000444314
610100011320325
7653440534403
oct144007714575
937575286648
1013423843709
115769456511
1227277500a5
13135c1410b3
14914b79473
1553877528e
hex3201f997d

13423843709 has 2 divisors, whose sum is σ = 13423843710. Its totient is φ = 13423843708.

The previous prime is 13423843651. The next prime is 13423843711. The reversal of 13423843709 is 90734832431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8090462809 + 5333380900 = 89947^2 + 73030^2 .

It is an emirp because it is prime and its reverse (90734832431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13423843709 is a prime.

Together with 13423843711, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13423843709.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13423843799) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6711921854 + 6711921855.

It is an arithmetic number, because the mean of its divisors is an integer number (6711921855).

Almost surely, 213423843709 is an apocalyptic number.

It is an amenable number.

13423843709 is a deficient number, since it is larger than the sum of its proper divisors (1).

13423843709 is an equidigital number, since it uses as much as digits as its factorization.

13423843709 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 435456, while the sum is 44.

The spelling of 13423843709 in words is "thirteen billion, four hundred twenty-three million, eight hundred forty-three thousand, seven hundred nine".