Base | Representation |
---|---|
bin | 11110100001011101111111… |
… | …011001100011110101100101 |
3 | 122121022100100210221121212122 |
4 | 132201131333121203311211 |
5 | 120043402231100241201 |
6 | 1153301341554555325 |
7 | 40163421361013354 |
oct | 3641357731436545 |
9 | 577270323847778 |
10 | 134241340243301 |
11 | 398564839a2725 |
12 | 13080a55298b45 |
13 | 59b9b9a30a7c5 |
14 | 252145bb8599b |
15 | 107bdd2e9de1b |
hex | 7a177f663d65 |
134241340243301 has 2 divisors, whose sum is σ = 134241340243302. Its totient is φ = 134241340243300.
The previous prime is 134241340243289. The next prime is 134241340243303. The reversal of 134241340243301 is 103342043142431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 127753265234401 + 6488075008900 = 11302799^2 + 2547170^2 .
It is an emirp because it is prime and its reverse (103342043142431) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134241340243301 is a prime.
Together with 134241340243303, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134241340243303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67120670121650 + 67120670121651.
It is an arithmetic number, because the mean of its divisors is an integer number (67120670121651).
Almost surely, 2134241340243301 is an apocalyptic number.
It is an amenable number.
134241340243301 is a deficient number, since it is larger than the sum of its proper divisors (1).
134241340243301 is an equidigital number, since it uses as much as digits as its factorization.
134241340243301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 134241340243301 its reverse (103342043142431), we get a palindrome (237583383385732).
The spelling of 134241340243301 in words is "one hundred thirty-four trillion, two hundred forty-one billion, three hundred forty million, two hundred forty-three thousand, three hundred one".
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