Base | Representation |
---|---|
bin | 11110100001011110101111… |
… | …001001001000010000111111 |
3 | 122121022102102122011121010002 |
4 | 132201132233021020100333 |
5 | 120043410401124224211 |
6 | 1153301553251104515 |
7 | 40163450255260655 |
oct | 3641365711102077 |
9 | 577272378147102 |
10 | 134242141242431 |
11 | 39856855056182 |
12 | 130810395a213b |
13 | 59b9c972503a1 |
14 | 25214d62d0dd5 |
15 | 107be2d47203b |
hex | 7a17af24843f |
134242141242431 has 2 divisors, whose sum is σ = 134242141242432. Its totient is φ = 134242141242430.
The previous prime is 134242141242427. The next prime is 134242141242437.
134242141242431 is nontrivially palindromic in base 10.
It is a weak prime.
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 134242141242431 - 22 = 134242141242427 is a prime.
It is a super-2 number, since 2×1342421412424312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134242141242437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67121070621215 + 67121070621216.
It is an arithmetic number, because the mean of its divisors is an integer number (67121070621216).
Almost surely, 2134242141242431 is an apocalyptic number.
134242141242431 is a deficient number, since it is larger than the sum of its proper divisors (1).
134242141242431 is an equidigital number, since it uses as much as digits as its factorization.
134242141242431 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 147456, while the sum is 38.
The spelling of 134242141242431 in words is "one hundred thirty-four trillion, two hundred forty-two billion, one hundred forty-one million, two hundred forty-two thousand, four hundred thirty-one".
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