Base | Representation |
---|---|
bin | 1100001101011001111010… |
… | …0111110010011000100000 |
3 | 1202112100210220000020100112 |
4 | 3003112132213302120200 |
5 | 3224421220102430422 |
6 | 44315033322510452 |
7 | 2553611663336660 |
oct | 303263647623040 |
9 | 52470726006315 |
10 | 13424434030112 |
11 | 43062a8043606 |
12 | 16098b3965428 |
13 | 764bc34ba831 |
14 | 345a633261a0 |
15 | 184301207ee2 |
hex | c359e9f2620 |
13424434030112 has 48 divisors (see below), whose sum is σ = 30356760470400. Its totient is φ = 5724417650688.
The previous prime is 13424434030099. The next prime is 13424434030123. The reversal of 13424434030112 is 21103043442431.
It is a super-2 number, since 2×134244340301122 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (32).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 150534593 + ... + 150623744.
It is an arithmetic number, because the mean of its divisors is an integer number (632432509800).
Almost surely, 213424434030112 is an apocalyptic number.
It is an amenable number.
13424434030112 is an abundant number, since it is smaller than the sum of its proper divisors (16932326440288).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13424434030112 is a wasteful number, since it uses less digits than its factorization.
13424434030112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 301158553 (or 301158545 counting only the distinct ones).
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 13424434030112 its reverse (21103043442431), we get a palindrome (34527477472543).
The spelling of 13424434030112 in words is "thirteen trillion, four hundred twenty-four billion, four hundred thirty-four million, thirty thousand, one hundred twelve".
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