Base | Representation |
---|---|
bin | 1100001101011001111010… |
… | …0111110011001110000110 |
3 | 1202112100210220000102001120 |
4 | 3003112132213303032012 |
5 | 3224421220103033132 |
6 | 44315033322534410 |
7 | 2553611663352660 |
oct | 303263647631606 |
9 | 52470726012046 |
10 | 13424434033542 |
11 | 43062a8046144 |
12 | 16098b3967406 |
13 | 764bc34bc26c |
14 | 345a63327530 |
15 | 18430120902c |
hex | c359e9f3386 |
13424434033542 has 64 divisors (see below), whose sum is σ = 31788981204480. Its totient is φ = 3697869821184.
The previous prime is 13424434033499. The next prime is 13424434033547. The reversal of 13424434033542 is 24533043442431.
It is a Harshad number since it is a multiple of its sum of digits (42).
It is a junction number, because it is equal to n+sod(n) for n = 13424434033494 and 13424434033503.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13424434033547) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7236703 + ... + 8900490.
It is an arithmetic number, because the mean of its divisors is an integer number (496702831320).
Almost surely, 213424434033542 is an apocalyptic number.
13424434033542 is an abundant number, since it is smaller than the sum of its proper divisors (18364547170938).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13424434033542 is a wasteful number, since it uses less digits than its factorization.
13424434033542 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16137917.
The product of its (nonzero) digits is 1658880, while the sum is 42.
Adding to 13424434033542 its reverse (24533043442431), we get a palindrome (37957477475973).
The spelling of 13424434033542 in words is "thirteen trillion, four hundred twenty-four billion, four hundred thirty-four million, thirty-three thousand, five hundred forty-two".
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