Base | Representation |
---|---|
bin | 111110100000110010… |
… | …1110101010111011100 |
3 | 110211111201120021120120 |
4 | 1331001211311113130 |
5 | 4144413033020012 |
6 | 141400535514540 |
7 | 12461462524551 |
oct | 1750145652734 |
9 | 424451507516 |
10 | 134244423132 |
11 | 51a29528046 |
12 | 22026228a50 |
13 | c875335401 |
14 | 66d7086a28 |
15 | 375a7ba58c |
hex | 1f419755dc |
134244423132 has 24 divisors (see below), whose sum is σ = 319147120656. Its totient is φ = 43903836288.
The previous prime is 134244423121. The next prime is 134244423193. The reversal of 134244423132 is 231324442431.
It is a nude number because it is divisible by every one of its digits.
It is a junction number, because it is equal to n+sod(n) for n = 134244423093 and 134244423102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 105537433 + ... + 105538704.
It is an arithmetic number, because the mean of its divisors is an integer number (13297796694).
Almost surely, 2134244423132 is an apocalyptic number.
134244423132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
134244423132 is an abundant number, since it is smaller than the sum of its proper divisors (184902697524).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134244423132 is a wasteful number, since it uses less digits than its factorization.
134244423132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 211076197 (or 211076195 counting only the distinct ones).
The product of its digits is 55296, while the sum is 33.
Adding to 134244423132 its reverse (231324442431), we get a palindrome (365568865563).
The spelling of 134244423132 in words is "one hundred thirty-four billion, two hundred forty-four million, four hundred twenty-three thousand, one hundred thirty-two".
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