Base | Representation |
---|---|
bin | 10011100010010001000… |
… | …011111100010111000111 |
3 | 11202100010120222002120001 |
4 | 103202101003330113013 |
5 | 133443331130320333 |
6 | 2504415204222131 |
7 | 165663332460622 |
oct | 23422103742707 |
9 | 4670116862501 |
10 | 1342463526343 |
11 | 478376732015 |
12 | 19821839a947 |
13 | 997946786a4 |
14 | 48d92dd0db9 |
15 | 24dc1d30b7d |
hex | 138910fc5c7 |
1342463526343 has 2 divisors, whose sum is σ = 1342463526344. Its totient is φ = 1342463526342.
The previous prime is 1342463526337. The next prime is 1342463526377. The reversal of 1342463526343 is 3436253642431.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1342463526343 is a prime.
It is a super-2 number, since 2×13424635263432 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1342463526293 and 1342463526302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1342463526323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671231763171 + 671231763172.
It is an arithmetic number, because the mean of its divisors is an integer number (671231763172).
Almost surely, 21342463526343 is an apocalyptic number.
1342463526343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342463526343 is an equidigital number, since it uses as much as digits as its factorization.
1342463526343 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3732480, while the sum is 46.
The spelling of 1342463526343 in words is "one trillion, three hundred forty-two billion, four hundred sixty-three million, five hundred twenty-six thousand, three hundred forty-three".
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