Base | Representation |
---|---|
bin | 111110100000111111… |
… | …0111011011000100111 |
3 | 110211112011221111020111 |
4 | 1331001332323120213 |
5 | 4144421224021013 |
6 | 141401332513451 |
7 | 12461602453252 |
oct | 1750176733047 |
9 | 424464844214 |
10 | 134251001383 |
11 | 51a32210414 |
12 | 2202847b887 |
13 | c8767c9675 |
14 | 66d7cba099 |
15 | 375b16973d |
hex | 1f41fbb627 |
134251001383 has 2 divisors, whose sum is σ = 134251001384. Its totient is φ = 134251001382.
The previous prime is 134251001321. The next prime is 134251001399. The reversal of 134251001383 is 383100152431.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134251001383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134251001783) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67125500691 + 67125500692.
It is an arithmetic number, because the mean of its divisors is an integer number (67125500692).
Almost surely, 2134251001383 is an apocalyptic number.
134251001383 is a deficient number, since it is larger than the sum of its proper divisors (1).
134251001383 is an equidigital number, since it uses as much as digits as its factorization.
134251001383 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 31.
The spelling of 134251001383 in words is "one hundred thirty-four billion, two hundred fifty-one million, one thousand, three hundred eighty-three".
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