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1342540452431 is a prime number
BaseRepresentation
bin10011100010010101101…
…001011001001001001111
311202100022221201100022102
4103202111221121021033
5133444010323434211
62504430553105315
7165665255362133
oct23422551311117
94670287640272
101342540452431
114784060a37a2
1219823a0b823b
13997a75a0899
1448d9d2d73c3
1524dc8978a3b
hex13895a5924f

1342540452431 has 2 divisors, whose sum is σ = 1342540452432. Its totient is φ = 1342540452430.

The previous prime is 1342540452401. The next prime is 1342540452439.

1342540452431 is nontrivially palindromic in base 10.

It is a strong prime.

It is a palprime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1342540452431 is a prime.

It is a super-2 number, since 2×13425404524312 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1342540452439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671270226215 + 671270226216.

It is an arithmetic number, because the mean of its divisors is an integer number (671270226216).

Almost surely, 21342540452431 is an apocalyptic number.

1342540452431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1342540452431 is an equidigital number, since it uses as much as digits as its factorization.

1342540452431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 230400, while the sum is 38.

It can be divided in two parts, 1342540 and 452431, that added together give a palindrome (1794971).

The spelling of 1342540452431 in words is "one trillion, three hundred forty-two billion, five hundred forty million, four hundred fifty-two thousand, four hundred thirty-one".