Base | Representation |
---|---|
bin | 10011100010010101101… |
… | …001011001001001001111 |
3 | 11202100022221201100022102 |
4 | 103202111221121021033 |
5 | 133444010323434211 |
6 | 2504430553105315 |
7 | 165665255362133 |
oct | 23422551311117 |
9 | 4670287640272 |
10 | 1342540452431 |
11 | 4784060a37a2 |
12 | 19823a0b823b |
13 | 997a75a0899 |
14 | 48d9d2d73c3 |
15 | 24dc8978a3b |
hex | 13895a5924f |
1342540452431 has 2 divisors, whose sum is σ = 1342540452432. Its totient is φ = 1342540452430.
The previous prime is 1342540452401. The next prime is 1342540452439.
1342540452431 is nontrivially palindromic in base 10.
It is a strong prime.
It is a palprime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1342540452431 is a prime.
It is a super-2 number, since 2×13425404524312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1342540452439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671270226215 + 671270226216.
It is an arithmetic number, because the mean of its divisors is an integer number (671270226216).
Almost surely, 21342540452431 is an apocalyptic number.
1342540452431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342540452431 is an equidigital number, since it uses as much as digits as its factorization.
1342540452431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 230400, while the sum is 38.
It can be divided in two parts, 1342540 and 452431, that added together give a palindrome (1794971).
The spelling of 1342540452431 in words is "one trillion, three hundred forty-two billion, five hundred forty million, four hundred fifty-two thousand, four hundred thirty-one".
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