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1342543100 = 225213425431
BaseRepresentation
bin101000000000101…
…1001010011111100
310110120020020220112
41100001121103330
510222142334400
6341115205152
745161266553
oct12001312374
93416206815
101342543100
11629915558
123157467b8
131851b2202
14ca436d9a
157cce5835
hex500594fc

1342543100 has 18 divisors (see below), whose sum is σ = 2913318744. Its totient is φ = 537017200.

The previous prime is 1342543099. The next prime is 1342543121. The reversal of 1342543100 is 13452431.

It is a super-2 number, since 2×13425431002 = 3604843950715220000, which contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 6712616 + ... + 6712815.

Almost surely, 21342543100 is an apocalyptic number.

1342543100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1342543100 is an abundant number, since it is smaller than the sum of its proper divisors (1570775644).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1342543100 is a wasteful number, since it uses less digits than its factorization.

1342543100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13425445 (or 13425438 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 1342543100 is about 36640.7300691457. The cubic root of 1342543100 is about 1103.1707687784.

Adding to 1342543100 its reverse (13452431), we get a palindrome (1355995531).

The spelling of 1342543100 in words is "one billion, three hundred forty-two million, five hundred forty-three thousand, one hundred".

Divisors: 1 2 4 5 10 20 25 50 100 13425431 26850862 53701724 67127155 134254310 268508620 335635775 671271550 1342543100