Base | Representation |
---|---|
bin | 1100001101011101101000… |
… | …0111001010100110000101 |
3 | 1202112110101110002000121121 |
4 | 3003113122013022212011 |
5 | 3224430241110031433 |
6 | 44315320335113541 |
7 | 2553645503030143 |
oct | 303273207124605 |
9 | 52473343060547 |
10 | 13425432111493 |
11 | 430676a476956 |
12 | 1609b320728b1 |
13 | 76502220562c |
14 | 345b19ad4593 |
15 | 18435db5ac2d |
hex | c35da1ca985 |
13425432111493 has 2 divisors, whose sum is σ = 13425432111494. Its totient is φ = 13425432111492.
The previous prime is 13425432111473. The next prime is 13425432111521. The reversal of 13425432111493 is 39411123452431.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6720864406369 + 6704567705124 = 2592463^2 + 2589318^2 .
It is a cyclic number.
It is not a de Polignac number, because 13425432111493 - 237 = 13287993158021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13425432111473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712716055746 + 6712716055747.
It is an arithmetic number, because the mean of its divisors is an integer number (6712716055747).
Almost surely, 213425432111493 is an apocalyptic number.
It is an amenable number.
13425432111493 is a deficient number, since it is larger than the sum of its proper divisors (1).
13425432111493 is an equidigital number, since it uses as much as digits as its factorization.
13425432111493 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 311040, while the sum is 43.
The spelling of 13425432111493 in words is "thirteen trillion, four hundred twenty-five billion, four hundred thirty-two million, one hundred eleven thousand, four hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •