Base | Representation |
---|---|
bin | 1100001101011101101111… |
… | …1110100100111011101111 |
3 | 1202112110110121222101021122 |
4 | 3003113123332210323233 |
5 | 3224430322113231021 |
6 | 44315323414051155 |
7 | 2553646333063451 |
oct | 303273376447357 |
9 | 52473417871248 |
10 | 13425463414511 |
11 | 4306786107315 |
12 | 1609b40649abb |
13 | 765028845725 |
14 | 345b1dd222d1 |
15 | 184361790bab |
hex | c35dbfa4eef |
13425463414511 has 2 divisors, whose sum is σ = 13425463414512. Its totient is φ = 13425463414510.
The previous prime is 13425463414483. The next prime is 13425463414547. The reversal of 13425463414511 is 11541436452431.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (11541436452431) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13425463414511 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13425463414591) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712731707255 + 6712731707256.
It is an arithmetic number, because the mean of its divisors is an integer number (6712731707256).
Almost surely, 213425463414511 is an apocalyptic number.
13425463414511 is a deficient number, since it is larger than the sum of its proper divisors (1).
13425463414511 is an equidigital number, since it uses as much as digits as its factorization.
13425463414511 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 691200, while the sum is 44.
Adding to 13425463414511 its reverse (11541436452431), we get a palindrome (24966899866942).
The spelling of 13425463414511 in words is "thirteen trillion, four hundred twenty-five billion, four hundred sixty-three million, four hundred fourteen thousand, five hundred eleven".
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