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13425524401453 is a prime number
BaseRepresentation
bin1100001101011101111110…
…0111001110010100101101
31202112110121212201211122021
43003113133213032110231
53224430433221321303
644315333433150141
72553651003341113
oct303273747162455
952473555654567
1013425524401453
11430680758174a
121609b58b5b351
13765038379988
14345b28079ab3
15184366cdaebd
hexc35df9ce52d

13425524401453 has 2 divisors, whose sum is σ = 13425524401454. Its totient is φ = 13425524401452.

The previous prime is 13425524401441. The next prime is 13425524401463. The reversal of 13425524401453 is 35410442552431.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9023072768649 + 4402451632804 = 3003843^2 + 2098202^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13425524401453 is a prime.

It is a super-2 number, since 2×134255244014532 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13425524401463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712762200726 + 6712762200727.

It is an arithmetic number, because the mean of its divisors is an integer number (6712762200727).

Almost surely, 213425524401453 is an apocalyptic number.

It is an amenable number.

13425524401453 is a deficient number, since it is larger than the sum of its proper divisors (1).

13425524401453 is an equidigital number, since it uses as much as digits as its factorization.

13425524401453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152000, while the sum is 43.

Adding to 13425524401453 its reverse (35410442552431), we get a palindrome (48835966953884).

The spelling of 13425524401453 in words is "thirteen trillion, four hundred twenty-five billion, five hundred twenty-four million, four hundred one thousand, four hundred fifty-three".