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134265064355599 is a prime number
BaseRepresentation
bin11110100001110100000101…
…011101110111011100001111
3122121101121121012001101210111
4132201310011131313130033
5120044244322433334344
61153320304041020451
740165221313441462
oct3641640535673417
9577347535041714
10134265064355599
1139865548600401
1213085576484727
1359bc1ab3cc188
14252266c8c72d9
15107c820b45834
hex7a1d0577770f

134265064355599 has 2 divisors, whose sum is σ = 134265064355600. Its totient is φ = 134265064355598.

The previous prime is 134265064355567. The next prime is 134265064355689. The reversal of 134265064355599 is 995553460562431.

It is a weak prime.

It is an emirp because it is prime and its reverse (995553460562431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134265064355599 - 25 = 134265064355567 is a prime.

It is a super-2 number, since 2×1342650643555992 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134265064355299) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67132532177799 + 67132532177800.

It is an arithmetic number, because the mean of its divisors is an integer number (67132532177800).

Almost surely, 2134265064355599 is an apocalyptic number.

134265064355599 is a deficient number, since it is larger than the sum of its proper divisors (1).

134265064355599 is an equidigital number, since it uses as much as digits as its factorization.

134265064355599 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 524880000, while the sum is 67.

The spelling of 134265064355599 in words is "one hundred thirty-four trillion, two hundred sixty-five billion, sixty-four million, three hundred fifty-five thousand, five hundred ninety-nine".