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134265064355689 is a prime number
BaseRepresentation
bin11110100001110100000101…
…011101110111011101101001
3122121101121121012001101220211
4132201310011131313131221
5120044244322433340224
61153320304041021121
740165221313441651
oct3641640535673551
9577347535041824
10134265064355689
1139865548600483
12130855764847a1
1359bc1ab3cc227
14252266c8c7361
15107c820b45894
hex7a1d05777769

134265064355689 has 2 divisors, whose sum is σ = 134265064355690. Its totient is φ = 134265064355688.

The previous prime is 134265064355599. The next prime is 134265064355707. The reversal of 134265064355689 is 986553460562431.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77218539358464 + 57046524997225 = 8787408^2 + 7552915^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134265064355689 is a prime.

It is not a weakly prime, because it can be changed into another prime (134265064355089) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67132532177844 + 67132532177845.

It is an arithmetic number, because the mean of its divisors is an integer number (67132532177845).

Almost surely, 2134265064355689 is an apocalyptic number.

It is an amenable number.

134265064355689 is a deficient number, since it is larger than the sum of its proper divisors (1).

134265064355689 is an equidigital number, since it uses as much as digits as its factorization.

134265064355689 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 559872000, while the sum is 67.

The spelling of 134265064355689 in words is "one hundred thirty-four trillion, two hundred sixty-five billion, sixty-four million, three hundred fifty-five thousand, six hundred eighty-nine".