Base | Representation |
---|---|
bin | 11001000000110001… |
… | …11000011001100111 |
3 | 1021122211201002010022 |
4 | 30200120320121213 |
5 | 210000120422041 |
6 | 10100250545355 |
7 | 653523424616 |
oct | 144030703147 |
9 | 37584632108 |
10 | 13428295271 |
11 | 5770a16a96 |
12 | 272913825b |
13 | 136003c361 |
14 | 9155b787d |
15 | 538d5424b |
hex | 320638667 |
13428295271 has 2 divisors, whose sum is σ = 13428295272. Its totient is φ = 13428295270.
The previous prime is 13428295219. The next prime is 13428295273. The reversal of 13428295271 is 17259282431.
It is a strong prime.
It is an emirp because it is prime and its reverse (17259282431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13428295271 - 214 = 13428278887 is a prime.
It is a super-2 number, since 2×134282952712 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
Together with 13428295273, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13428295273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6714147635 + 6714147636.
It is an arithmetic number, because the mean of its divisors is an integer number (6714147636).
Almost surely, 213428295271 is an apocalyptic number.
13428295271 is a deficient number, since it is larger than the sum of its proper divisors (1).
13428295271 is an equidigital number, since it uses as much as digits as its factorization.
13428295271 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 241920, while the sum is 44.
The spelling of 13428295271 in words is "thirteen billion, four hundred twenty-eight million, two hundred ninety-five thousand, two hundred seventy-one".
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