Base | Representation |
---|---|
bin | 1100001101101111111101… |
… | …0100000100110100111111 |
3 | 1202112221002021020121221201 |
4 | 3003123333110010310333 |
5 | 3230020324403020111 |
6 | 44321452420440331 |
7 | 2554211423536354 |
oct | 303337724046477 |
9 | 52487067217851 |
10 | 13430351220031 |
11 | 4308864153a09 |
12 | 160aa855490a7 |
13 | 765627381145 |
14 | 34606513a62b |
15 | 18454a9346c1 |
hex | c36ff504d3f |
13430351220031 has 2 divisors, whose sum is σ = 13430351220032. Its totient is φ = 13430351220030.
The previous prime is 13430351220007. The next prime is 13430351220101. The reversal of 13430351220031 is 13002215303431.
It is a weak prime.
It is an emirp because it is prime and its reverse (13002215303431) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13430351220031 is a prime.
It is a super-2 number, since 2×134303512200312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13430351220331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6715175610015 + 6715175610016.
It is an arithmetic number, because the mean of its divisors is an integer number (6715175610016).
Almost surely, 213430351220031 is an apocalyptic number.
13430351220031 is a deficient number, since it is larger than the sum of its proper divisors (1).
13430351220031 is an equidigital number, since it uses as much as digits as its factorization.
13430351220031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 13430351220031 its reverse (13002215303431), we get a palindrome (26432566523462).
The spelling of 13430351220031 in words is "thirteen trillion, four hundred thirty billion, three hundred fifty-one million, two hundred twenty thousand, thirty-one".
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