Base | Representation |
---|---|
bin | 1100001101110001110101… |
… | …1100111101000000011011 |
3 | 1202112222101111200222202122 |
4 | 3003130131130331000123 |
5 | 3230022343324120041 |
6 | 44322014522251455 |
7 | 2554230103460354 |
oct | 303343534750033 |
9 | 52488344628678 |
10 | 13430856863771 |
11 | 4308aa36155a6 |
12 | 160aba6956b8b |
13 | 7656a8061019 |
14 | 3460b2360d2b |
15 | 18457a014c4b |
hex | c371d73d01b |
13430856863771 has 2 divisors, whose sum is σ = 13430856863772. Its totient is φ = 13430856863770.
The previous prime is 13430856863759. The next prime is 13430856863773. The reversal of 13430856863771 is 17736865803431.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13430856863771 is a prime.
Together with 13430856863773, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13430856863773) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6715428431885 + 6715428431886.
It is an arithmetic number, because the mean of its divisors is an integer number (6715428431886).
Almost surely, 213430856863771 is an apocalyptic number.
13430856863771 is a deficient number, since it is larger than the sum of its proper divisors (1).
13430856863771 is an equidigital number, since it uses as much as digits as its factorization.
13430856863771 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60963840, while the sum is 62.
The spelling of 13430856863771 in words is "thirteen trillion, four hundred thirty billion, eight hundred fifty-six million, eight hundred sixty-three thousand, seven hundred seventy-one".
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