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13430856863777 is a prime number
BaseRepresentation
bin1100001101110001110101…
…1100111101000000100001
31202112222101111200222202212
43003130131130331000201
53230022343324120102
644322014522251505
72554230103460363
oct303343534750041
952488344628685
1013430856863777
114308aa3615601
12160aba6956b95
137656a8061022
143460b2360d33
1518457a014c52
hexc371d73d021

13430856863777 has 2 divisors, whose sum is σ = 13430856863778. Its totient is φ = 13430856863776.

The previous prime is 13430856863773. The next prime is 13430856863779. The reversal of 13430856863777 is 77736865803431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8235757779601 + 5195099084176 = 2869801^2 + 2279276^2 .

It is an emirp because it is prime and its reverse (77736865803431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13430856863777 - 22 = 13430856863773 is a prime.

Together with 13430856863779, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13430856863771) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6715428431888 + 6715428431889.

It is an arithmetic number, because the mean of its divisors is an integer number (6715428431889).

Almost surely, 213430856863777 is an apocalyptic number.

It is an amenable number.

13430856863777 is a deficient number, since it is larger than the sum of its proper divisors (1).

13430856863777 is an equidigital number, since it uses as much as digits as its factorization.

13430856863777 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 426746880, while the sum is 68.

The spelling of 13430856863777 in words is "thirteen trillion, four hundred thirty billion, eight hundred fifty-six million, eight hundred sixty-three thousand, seven hundred seventy-seven".