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13431405012000 = 253534001279751
BaseRepresentation
bin1100001101110011111000…
…0111111110010000100000
31202120000210201010210202220
43003130332013332100200
53230030004140341000
644322145143111040
72554246510610223
oct303347607762040
952500721123686
1013431405012000
114309254a78468
12160b11a442480
137657647a36a1
1434612508b5ba
151845ad1de1a0
hexc373e1fe420

13431405012000 has 192 divisors, whose sum is σ = 44012437717248. Its totient is φ = 3580800000000.

The previous prime is 13431405011951. The next prime is 13431405012023. The reversal of 13431405012000 is 21050413431.

It is a happy number.

13431405012000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 47872125 + ... + 48151875.

It is an arithmetic number, because the mean of its divisors is an integer number (229231446444).

Almost surely, 213431405012000 is an apocalyptic number.

13431405012000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13431405012000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22006218858624).

13431405012000 is an abundant number, since it is smaller than the sum of its proper divisors (30581032705248).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13431405012000 is a wasteful number, since it uses less digits than its factorization.

13431405012000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 283780 (or 283762 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 13431405012000 its reverse (21050413431), we get a palindrome (13452455425431).

The spelling of 13431405012000 in words is "thirteen trillion, four hundred thirty-one billion, four hundred five million, twelve thousand".