Base | Representation |
---|---|
bin | 111110100010111001… |
… | …1111010110000111101 |
3 | 110211200122210100021120 |
4 | 1331011303322300331 |
5 | 4200034144133000 |
6 | 141411545221153 |
7 | 12463312365465 |
oct | 1750563726075 |
9 | 424618710246 |
10 | 134315224125 |
11 | 51a65495965 |
12 | 22045a917b9 |
13 | c886bc46a4 |
14 | 6702636ba5 |
15 | 3761b036a0 |
hex | 1f45cfac3d |
134315224125 has 64 divisors (see below), whose sum is σ = 225007411200. Its totient is φ = 71153121600.
The previous prime is 134315224123. The next prime is 134315224139. The reversal of 134315224125 is 521422513431.
It is not a de Polignac number, because 134315224125 - 21 = 134315224123 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134315224123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 58728732 + ... + 58731018.
It is an arithmetic number, because the mean of its divisors is an integer number (3515740800).
Almost surely, 2134315224125 is an apocalyptic number.
134315224125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
134315224125 is a deficient number, since it is larger than the sum of its proper divisors (90692187075).
134315224125 is a wasteful number, since it uses less digits than its factorization.
134315224125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3291 (or 3281 counting only the distinct ones).
The product of its digits is 28800, while the sum is 33.
Adding to 134315224125 its reverse (521422513431), we get a palindrome (655737737556).
The spelling of 134315224125 in words is "one hundred thirty-four billion, three hundred fifteen million, two hundred twenty-four thousand, one hundred twenty-five".
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