Base | Representation |
---|---|
bin | 1100001101110100011001… |
… | …0011010100110001100100 |
3 | 1202120001011021021221221010 |
4 | 3003131012103110301210 |
5 | 3230030244301034130 |
6 | 44322210523422220 |
7 | 2554253065001334 |
oct | 303350623246144 |
9 | 52501137257833 |
10 | 13431542205540 |
11 | 4309315462a58 |
12 | 160b158384970 |
13 | 76578703a4b4 |
14 | 3461393a10c4 |
15 | 1845ba28e0b0 |
hex | c37464d4c64 |
13431542205540 has 24 divisors (see below), whose sum is σ = 37608318175680. Its totient is φ = 3581744588128.
The previous prime is 13431542205353. The next prime is 13431542205559. The reversal of 13431542205540 is 4550224513431.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 111929518320 + ... + 111929518439.
It is an arithmetic number, because the mean of its divisors is an integer number (1567013257320).
Almost surely, 213431542205540 is an apocalyptic number.
13431542205540 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13431542205540 is an abundant number, since it is smaller than the sum of its proper divisors (24176775970140).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13431542205540 is a wasteful number, since it uses less digits than its factorization.
13431542205540 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 223859036771 (or 223859036769 counting only the distinct ones).
The product of its (nonzero) digits is 288000, while the sum is 39.
Adding to 13431542205540 its reverse (4550224513431), we get a palindrome (17981766718971).
The spelling of 13431542205540 in words is "thirteen trillion, four hundred thirty-one billion, five hundred forty-two million, two hundred five thousand, five hundred forty".
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