134331132031 has 2 divisors, whose sum is σ = 134331132032. Its totient is φ = 134331132030.

The previous prime is 134331132017. The next prime is 134331132037. The reversal of 134331132031 is 130231133431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134331132031 - 2⁵ = 134331131999 is a prime.

It is a super-2 number, since 2×134331132031² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 134331131987 and 134331132005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134331132037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67165566015 + 67165566016.

It is an arithmetic number, because the mean of its divisors is an integer number (67165566016).

Almost surely, 2^134331132031 is an apocalyptic number.

134331132031 is a deficient number, since it is larger than the sum of its proper divisors (1).

134331132031 is an equidigital number, since it uses as much as digits as its factorization.

134331132031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 134331132031 its reverse (130231133431), we get a palindrome (264562265462).

The spelling of 134331132031 in words is "one hundred thirty-four billion, three hundred thirty-one million, one hundred thirty-two thousand, thirty-one".