134331140100330 has 48 divisors (see below), whose sum is σ = 349538375964960. Its totient is φ = 35793184877664.

The previous prime is 134331140100329. The next prime is 134331140100379. The reversal of 134331140100330 is 33001041133431.

134331140100330 is a `hidden beast` number, since 1 + 3 + 4 + 3 + 311 + 4 + 0 + 10 + 0 + 330 = 666.

It is a super-2 number, since 2×134331140100330² (a number of 29 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 134331140100294 and 134331140100303.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 592646112 + ... + 592872731.

It is an arithmetic number, because the mean of its divisors is an integer number (7282049499270).

Almost surely, 2^{134331140100330} is an apocalyptic number.

134331140100330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

134331140100330 is an abundant number, since it is smaller than the sum of its proper divisors (215207235864630).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134331140100330 is a wasteful number, since it uses less digits than its factorization.

134331140100330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1185520115 (or 1185520112 counting only the distinct ones).

The product of its (nonzero) digits is 3888, while the sum is 27.

Adding to 134331140100330 its reverse (33001041133431), we get a palindrome (167332181233761).

The spelling of 134331140100330 in words is "one hundred thirty-four trillion, three hundred thirty-one billion, one hundred forty million, one hundred thousand, three hundred thirty".