Base | Representation |
---|---|
bin | 11110100010110001111010… |
… | …000101111001000110101111 |
3 | 122121121221221101220200011121 |
4 | 132202301322011321012233 |
5 | 120101341300022432141 |
6 | 1153411003015401411 |
7 | 40203061306125466 |
oct | 3642617205710657 |
9 | 577557841820147 |
10 | 134331445514671 |
11 | 39890711a85749 |
12 | 13096401383267 |
13 | 59c5529b9aa22 |
14 | 2525968a479dd |
15 | 107e4086c21d1 |
hex | 7a2c7a1791af |
134331445514671 has 2 divisors, whose sum is σ = 134331445514672. Its totient is φ = 134331445514670.
The previous prime is 134331445514647. The next prime is 134331445514681. The reversal of 134331445514671 is 176415544133431.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134331445514671 is a prime.
It is a super-2 number, since 2×1343314455146712 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134331445514681) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67165722757335 + 67165722757336.
It is an arithmetic number, because the mean of its divisors is an integer number (67165722757336).
Almost surely, 2134331445514671 is an apocalyptic number.
134331445514671 is a deficient number, since it is larger than the sum of its proper divisors (1).
134331445514671 is an equidigital number, since it uses as much as digits as its factorization.
134331445514671 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7257600, while the sum is 52.
The spelling of 134331445514671 in words is "one hundred thirty-four trillion, three hundred thirty-one billion, four hundred forty-five million, five hundred fourteen thousand, six hundred seventy-one".
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