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13433200423 is a prime number
BaseRepresentation
bin11001000001010111…
…00101111100100111
31021200011221021201121
430200223211330213
5210002344403143
610100544034411
7653613214426
oct144053457447
937604837647
1013433200423
115773767335
12272a902a07
131361068c06
149160d32bd
155394c27ed
hex320ae5f27

13433200423 has 2 divisors, whose sum is σ = 13433200424. Its totient is φ = 13433200422.

The previous prime is 13433200381. The next prime is 13433200433. The reversal of 13433200423 is 32400233431.

It is a strong prime.

It is an emirp because it is prime and its reverse (32400233431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13433200423 - 213 = 13433192231 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13433200433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6716600211 + 6716600212.

It is an arithmetic number, because the mean of its divisors is an integer number (6716600212).

Almost surely, 213433200423 is an apocalyptic number.

13433200423 is a deficient number, since it is larger than the sum of its proper divisors (1).

13433200423 is an equidigital number, since it uses as much as digits as its factorization.

13433200423 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 13433200423 its reverse (32400233431), we get a palindrome (45833433854).

The spelling of 13433200423 in words is "thirteen billion, four hundred thirty-three million, two hundred thousand, four hundred twenty-three".