Base | Representation |
---|---|
bin | 11001000001011001… |
… | …11001001010110101 |
3 | 1021200012120121022201 |
4 | 30200230321022311 |
5 | 210002441310201 |
6 | 10100555224501 |
7 | 653616134305 |
oct | 144054711265 |
9 | 37605517281 |
10 | 13433541301 |
11 | 577397a454 |
12 | 272aa48131 |
13 | 136115810b |
14 | 916181605 |
15 | 53953d801 |
hex | 320b392b5 |
13433541301 has 2 divisors, whose sum is σ = 13433541302. Its totient is φ = 13433541300.
The previous prime is 13433541263. The next prime is 13433541311. The reversal of 13433541301 is 10314533431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12499016401 + 934524900 = 111799^2 + 30570^2 .
It is a cyclic number.
It is not a de Polignac number, because 13433541301 - 215 = 13433508533 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13433541301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13433541311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6716770650 + 6716770651.
It is an arithmetic number, because the mean of its divisors is an integer number (6716770651).
Almost surely, 213433541301 is an apocalyptic number.
It is an amenable number.
13433541301 is a deficient number, since it is larger than the sum of its proper divisors (1).
13433541301 is an equidigital number, since it uses as much as digits as its factorization.
13433541301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 28.
The spelling of 13433541301 in words is "thirteen billion, four hundred thirty-three million, five hundred forty-one thousand, three hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •