Base | Representation |
---|---|
bin | 1100001101111110000101… |
… | …1000110001011001111101 |
3 | 1202120021212121012222220011 |
4 | 3003133201120301121331 |
5 | 3230101111342231023 |
6 | 44323321031223221 |
7 | 2554404420521335 |
oct | 303374130613175 |
9 | 52507777188804 |
10 | 13434144102013 |
11 | 430a430133318 |
12 | 160b763817b11 |
13 | 765ab00c56cb |
14 | 346304b780c5 |
15 | 1846bd8e650d |
hex | c37e163167d |
13434144102013 has 2 divisors, whose sum is σ = 13434144102014. Its totient is φ = 13434144102012.
The previous prime is 13434144101957. The next prime is 13434144102073. The reversal of 13434144102013 is 31020144143431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9697724689689 + 3736419412324 = 3114117^2 + 1932982^2 .
It is a cyclic number.
It is not a de Polignac number, because 13434144102013 - 229 = 13433607231101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13434144102073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6717072051006 + 6717072051007.
It is an arithmetic number, because the mean of its divisors is an integer number (6717072051007).
Almost surely, 213434144102013 is an apocalyptic number.
It is an amenable number.
13434144102013 is a deficient number, since it is larger than the sum of its proper divisors (1).
13434144102013 is an equidigital number, since it uses as much as digits as its factorization.
13434144102013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 13434144102013 its reverse (31020144143431), we get a palindrome (44454288245444).
The spelling of 13434144102013 in words is "thirteen trillion, four hundred thirty-four billion, one hundred forty-four million, one hundred two thousand, thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •