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13434144101957 is a prime number
BaseRepresentation
bin1100001101111110000101…
…1000110001011001000101
31202120021212121012222211002
43003133201120301121011
53230101111342230312
644323321031223045
72554404420521225
oct303374130613105
952507777188732
1013434144101957
11430a430133277
12160b763817a85
13765ab00c5687
14346304b78085
151846bd8e64c2
hexc37e1631645

13434144101957 has 2 divisors, whose sum is σ = 13434144101958. Its totient is φ = 13434144101956.

The previous prime is 13434144101827. The next prime is 13434144102013. The reversal of 13434144101957 is 75910144143431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9406893848356 + 4027250253601 = 3067066^2 + 2006801^2 .

It is a cyclic number.

It is not a de Polignac number, because 13434144101957 - 212 = 13434144097861 is a prime.

It is a super-2 number, since 2×134341441019572 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13434144104957) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6717072050978 + 6717072050979.

It is an arithmetic number, because the mean of its divisors is an integer number (6717072050979).

Almost surely, 213434144101957 is an apocalyptic number.

It is an amenable number.

13434144101957 is a deficient number, since it is larger than the sum of its proper divisors (1).

13434144101957 is an equidigital number, since it uses as much as digits as its factorization.

13434144101957 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 725760, while the sum is 47.

The spelling of 13434144101957 in words is "thirteen trillion, four hundred thirty-four billion, one hundred forty-four million, one hundred one thousand, nine hundred fifty-seven".