13434241421 has 2 divisors, whose sum is σ = 13434241422. Its totient is φ = 13434241420.

The previous prime is 13434241411. The next prime is 13434241423. The reversal of 13434241421 is 12414243431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12726096100 + 708145321 = 112810^2 + 26611^2 .

It is an emirp because it is prime and its reverse (12414243431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13434241421 - 2¹⁴ = 13434225037 is a prime.

Together with 13434241423, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13434241423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6717120710 + 6717120711.

It is an arithmetic number, because the mean of its divisors is an integer number (6717120711).

Almost surely, 2^13434241421 is an apocalyptic number.

It is an amenable number.

13434241421 is a deficient number, since it is larger than the sum of its proper divisors (1).

13434241421 is an equidigital number, since it uses as much as digits as its factorization.

13434241421 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 9216, while the sum is 29.

Adding to 13434241421 its reverse (12414243431), we get a palindrome (25848484852).

The spelling of 13434241421 in words is "thirteen billion, four hundred thirty-four million, two hundred forty-one thousand, four hundred twenty-one".