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1343440143317 is a prime number
BaseRepresentation
bin10011100011001011010…
…001011100001111010101
311202102122122122101012002
4103203023101130033111
5134002331134041232
62505100132405045
7166026461542466
oct23431321341725
94672578571162
101343440143317
11478827a34888
1219844b476785
13998bbab965c
14490469b2d6d
1524e2c943b62
hex138cb45c3d5

1343440143317 has 2 divisors, whose sum is σ = 1343440143318. Its totient is φ = 1343440143316.

The previous prime is 1343440143271. The next prime is 1343440143361. The reversal of 1343440143317 is 7133410443431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1327025665156 + 16414478161 = 1151966^2 + 128119^2 .

It is an emirp because it is prime and its reverse (7133410443431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1343440143317 - 210 = 1343440142293 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1343440143377) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671720071658 + 671720071659.

It is an arithmetic number, because the mean of its divisors is an integer number (671720071659).

Almost surely, 21343440143317 is an apocalyptic number.

It is an amenable number.

1343440143317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1343440143317 is an equidigital number, since it uses as much as digits as its factorization.

1343440143317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 145152, while the sum is 38.

Adding to 1343440143317 its reverse (7133410443431), we get a palindrome (8476850586748).

The spelling of 1343440143317 in words is "one trillion, three hundred forty-three billion, four hundred forty million, one hundred forty-three thousand, three hundred seventeen".