13434440440441 has 2 divisors, whose sum is σ = 13434440440442. Its totient is φ = 13434440440440.

The previous prime is 13434440440427. The next prime is 13434440440481. The reversal of 13434440440441 is 14404404443431.

It is an a-pointer prime, because the next prime (13434440440481) can be obtained adding 13434440440441 to its sum of digits (40).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13260631495225 + 173808945216 = 3641515^2 + 416904^2 .

It is an emirp because it is prime and its reverse (14404404443431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13434440440441 - 2⁷ = 13434440440313 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13434440440394 and 13434440440403.

It is not a weakly prime, because it can be changed into another prime (13434440440411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6717220220220 + 6717220220221.

It is an arithmetic number, because the mean of its divisors is an integer number (6717220220221).

Almost surely, 2^{13434440440441} is an apocalyptic number.

It is an amenable number.

13434440440441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13434440440441 is an equidigital number, since it uses as much as digits as its factorization.

13434440440441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 589824, while the sum is 40.

Adding to 13434440440441 its reverse (14404404443431), we get a palindrome (27838844883872).

The spelling of 13434440440441 in words is "thirteen trillion, four hundred thirty-four billion, four hundred forty million, four hundred forty thousand, four hundred forty-one".