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1343461255469 is a prime number
BaseRepresentation
bin10011100011001100100…
…001111110100100101101
311202102201010100222121122
4103203030201332210231
5134002402040133334
62505102205110325
7166030136153114
oct23431441764455
94672633328548
101343461255469
11478838944743
121984565583a5
13998c329c058
144904970ac7b
1524e2e71432e
hex138cc87e92d

1343461255469 has 2 divisors, whose sum is σ = 1343461255470. Its totient is φ = 1343461255468.

The previous prime is 1343461255453. The next prime is 1343461255523. The reversal of 1343461255469 is 9645521643431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1018747048900 + 324714206569 = 1009330^2 + 569837^2 .

It is a cyclic number.

It is not a de Polignac number, because 1343461255469 - 24 = 1343461255453 is a prime.

It is a super-2 number, since 2×13434612554692 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1343461255469.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1343461255069) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671730627734 + 671730627735.

It is an arithmetic number, because the mean of its divisors is an integer number (671730627735).

Almost surely, 21343461255469 is an apocalyptic number.

It is an amenable number.

1343461255469 is a deficient number, since it is larger than the sum of its proper divisors (1).

1343461255469 is an equidigital number, since it uses as much as digits as its factorization.

1343461255469 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 9331200, while the sum is 53.

The spelling of 1343461255469 in words is "one trillion, three hundred forty-three billion, four hundred sixty-one million, two hundred fifty-five thousand, four hundred sixty-nine".