Base | Representation |
---|---|
bin | 11110100011000011100101… |
… | …010011010001001010110111 |
3 | 122121200202221001101021121122 |
4 | 132203003211103101022313 |
5 | 120102144132024134112 |
6 | 1153423422135334155 |
7 | 40204332516052343 |
oct | 3643034523211267 |
9 | 577622831337548 |
10 | 134350424052407 |
11 | 39898770961a82 |
12 | 1309a01922135b |
13 | 59c7262a62604 |
14 | 25268493d6623 |
15 | 107eb6991c872 |
hex | 7a30e54d12b7 |
134350424052407 has 2 divisors, whose sum is σ = 134350424052408. Its totient is φ = 134350424052406.
The previous prime is 134350424052347. The next prime is 134350424052437. The reversal of 134350424052407 is 704250424053431.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134350424052407 - 230 = 134349350310583 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134350424052437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67175212026203 + 67175212026204.
It is an arithmetic number, because the mean of its divisors is an integer number (67175212026204).
Almost surely, 2134350424052407 is an apocalyptic number.
134350424052407 is a deficient number, since it is larger than the sum of its proper divisors (1).
134350424052407 is an equidigital number, since it uses as much as digits as its factorization.
134350424052407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1612800, while the sum is 44.
The spelling of 134350424052407 in words is "one hundred thirty-four trillion, three hundred fifty billion, four hundred twenty-four million, fifty-two thousand, four hundred seven".
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