Base | Representation |
---|---|
bin | 11110100011000100100010… |
… | …000110100110011101001111 |
3 | 122121200212120010212012100002 |
4 | 132203010202012212131033 |
5 | 120102203224200020103 |
6 | 1153424111255354515 |
7 | 40204400013504242 |
oct | 3643044206463517 |
9 | 577625503765302 |
10 | 134351444141903 |
11 | 3989914475734a |
12 | 1309a262982a3b |
13 | 59c73961b4871 |
14 | 2526904a93259 |
15 | 107ebc926b488 |
hex | 7a31221a674f |
134351444141903 has 2 divisors, whose sum is σ = 134351444141904. Its totient is φ = 134351444141902.
The previous prime is 134351444141867. The next prime is 134351444141909. The reversal of 134351444141903 is 309141444153431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134351444141903 - 26 = 134351444141839 is a prime.
It is a super-2 number, since 2×1343514441419032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134351444141909) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67175722070951 + 67175722070952.
It is an arithmetic number, because the mean of its divisors is an integer number (67175722070952).
Almost surely, 2134351444141903 is an apocalyptic number.
134351444141903 is a deficient number, since it is larger than the sum of its proper divisors (1).
134351444141903 is an equidigital number, since it uses as much as digits as its factorization.
134351444141903 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1244160, while the sum is 47.
The spelling of 134351444141903 in words is "one hundred thirty-four trillion, three hundred fifty-one billion, four hundred forty-four million, one hundred forty-one thousand, nine hundred three".
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