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134352154343000 = 23531123593309031
BaseRepresentation
bin11110100011000101001100…
…011011110011011001011000
3122121200221101122020011002102
4132203011030123303121120
5120102211203002434000
61153424305545422532
740204423426223336
oct3643051433633130
9577627348204072
10134352154343000
1139899479633a00
121309a42079aa48
1359c747a3861b9
142526971124b56
15107ec1b7a63d5
hex7a314c6f3658

134352154343000 has 192 divisors, whose sum is σ = 345659918909760. Its totient is φ = 48841573440000.

The previous prime is 134352154342949. The next prime is 134352154343021. The reversal of 134352154343000 is 343451253431.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 434598485 + ... + 434907515.

It is an arithmetic number, because the mean of its divisors is an integer number (1800312077655).

Almost surely, 2134352154343000 is an apocalyptic number.

134352154343000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 134352154343000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (172829959454880).

134352154343000 is an abundant number, since it is smaller than the sum of its proper divisors (211307764566760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134352154343000 is a wasteful number, since it uses less digits than its factorization.

134352154343000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 312667 (or 312642 counting only the distinct ones).

The product of its (nonzero) digits is 259200, while the sum is 38.

The spelling of 134352154343000 in words is "one hundred thirty-four trillion, three hundred fifty-two billion, one hundred fifty-four million, three hundred forty-three thousand".